Math Puzzler fun

Accipiter

0		0		0	=	6
1		1		1	=	6
2	+	2	+	2	=	6  // solved for you
3		3		3	=	6
4		4		4	=	6
5		5		5	=	6
6		6		6	=	6
7		7		7	=	6
8		8		8	=	6
9		9		9	=	6

make each row equal to 6 using ONLY symbols
(e.g. these symbols + - ( ) / * sqrt or ! (factorial), as well as others.)


you cannot use exponents.

but you can use square root e.g. the square root of 4 is 2
e.g.

sqrt 4 = 2

and you can use factorials as well
e.g.

3! - 3 factorial is 6
3 x 2 1 = 6

4! - 4 factorial
4 *3*2*1 = 24

put any number of symbols around any of the numbers of the left hand side of equation

any takers.

10 points for each correct line solved 10 lines solved 100%

what was your score?

DavidV

I scored 100%. The most challenging in the first one:

(cos(0) + cos(0) + cos(0))! = 6

Accipiter

@DavidV
(cos(0) + cos(0) + cos(0))! = 6

really, realy close but you can't use the cos


you got the right idea - but you can't use cos sine tangent just symbols.
if you add letters they are not symbols.

so we need a new answer on the first line.

0		0		0	=	6

hint here: http://mathforum.org/library/drmath/view/57128.html

finder

(0!+0!+0!)! = 6

msf

DavidV basically gave the solution, but worked too hard at it. Factorial (no trig) is all that's needed. 0! = 1 = cos(0).

Edit: posted before reading your hint.

Accipiter

⍟

ǝɹǝɥ sɹǝʍsu∀

9	=	6ʇɹbs /	(6	+	6)

9	=	¡(8	+	(8	/	8))

9	=	(ㄥ	/	ㄥ)	-	ㄥ

9	=	9	*	(9	/	9)

9	=	(ϛ	/	ϛ)	+	ϛ

9	=	ㄣʇɹbs	+	ㄣʇɹbs	+	ㄣʇɹbs

9	=	Ɛ	-	(Ɛ	*	Ɛ)


9	=	¡(Ɩ	+	Ɩ	+	Ɩ)

9	=	¡(¡0	+	¡0	+	¡0)

msf

Are you sure about #8? (9!)?

Though writing the whole expression upside down does offer an outside the box solution:
(8 + 8/8) = 9. Turning it upside down, the eights remain eights and the nine becomes six

Allow cube roots and the problem becomes simple.

Accipiter

>Are you sure about #8? (9!)?

>Though writing the whole expression upside down does offer an outside the box solution:
(8 + 8/8) = 9. Turning it upside down, the eights remain eights and the nine becomes six



nice spot of incorrect solution @msf and a good out of the box explanation
right you are, the answer displayed was lacking the crucial (square root of 9)! = 3! = 3* 2+ 1 = 6



    ⎯ ⎯ ⎯ ⎯ ⎯ ⎯ ⎯
(√((8 / 8) + 8))! = 6



(0! + 0! + 0!)! = 6

(1 + 1 + 1)! = 6

2 + 2 + 2 = 6 // solved for you3

(3 * 3) - 3 = 6

sqrt4 + sqrt4 + sqrt4 = 6

5 + (5 / 5) = 6

(6 / 6) * 6 = 6

7 - (7 / 7) = 6


(9 + 9) / sqrt9 = 6